While the actual equation in question is x' = x - vt, this paper will only be addressing the related math equation x' = x - distance. First, the reader be shown the two starting conditions ( each having coincident coordinate systems) as given by the Galilean. One case is called the active version, which commences with a point only in one system. The second case is called the passive version which commences with a corresponding point in both systems. Before the challenge itself, a depiction will be shown to represents the results of performing the Galilean transformation...with an example: x = 2 and vt in the S' frame = d = 3.