DIAGONAL RAMSEY NUMBERS
"WATERMAN CONJECTURE of 2010"

As of September 2010...I changed the lettering assigned in my formulas to better comply with standard lettering....however, all my conjectured Ramsey values remained totally unchanged.

     "Erdo"s asks us to imagine an alien force, vastly more powerful than us, landing on Earth and demanding the value of R(5, 5) or they will destroy our planet. In that case, he claims, we should marshal all our computers and all our mathematicians and attempt to find the value. But suppose, instead, that they ask for R(6, 6). In that case, he believes, we should attempt to destroy the aliens."

Perhaps we could just use my formula below, instead ?
The classic Ramsey problem can be phrased in terms of guests at a party. What is the minimum number of guests at a party that need to be invited so that either at least three guests will all know each other or be mutual strangers? Answer 6. Suppose we want not a threesome but a foursome who either know each other or are mutual strangers? Erdos and Ramsey theorists have proved that 18 guests are required. For a fivesome, that answer is believed to be 43 to 49. For a sixsome...102 to 165.
I propose the following values (for numbers up to a trillion) are for additional levels, without any proof..."the Waterman diagonal Ramsey conjecture". Values have been obtained through the use of my following formula

R = s(s-1) 2 k-s
where R = Ramsey number
k = discussion group size and s = size of the unit group

s = 3
k
Ramsey number = R
known limits
s
(k-1)
2 k-s
366321
41818332
54843-49344
6120102-165358
7288205-5403616
8672282-18703732
91,536565-65883864
103,456798-2355639128
117,6801597-184755310256
1216,8961837-705431311512
1336,8642557-27041553121,024
1479,8722989-104005993132,048
15172,0325485-401165993144,096
16368,6405605-1551175193158,192
17786,4328917-60108038931616,384
181,671,16811005-233360621931732,768
193,538,94417885-907513529931865,536
207,471,104319131,072
2115,728,640320262,144
2233,030,144321524,288
2369,208,0163221,048,576
24144,703,4883232,097,152
25301,989,8883244,194,304
26629,145,6003258,388,608
271,308,622,84832616,777,216
282,717,908,99232733,554,432
295,637,144,57632887,108,864
3011,676,942,336329134,217,728
3124,159,191,040330268,435,456
3249,928,994,816331536,870,912
33103,079,215,1043321,073,741,824
34212,600,881,1523332,147,483,648
35438,086,664,1923344,294,967,296
36901,943,132,1603358,589,934,592

The classic Ramsey problem only relates 3 guests as a basic unit. The stipulation is that any 3 guests which arrive together must be either strangers or be acquainted. However, what if this unit group of 3 guests were extended to a unit group of 4 guests. That is, invited guests arrive in blocks of 4, all of which must be either mutually acquainted or all strangers to one another. Later, they can mingle indisciminately. The charts below indicate these increased unit groups for all additional Ramsey values up to a trillion.
I also have conject regarding a more generalized formula for these "supplimentary" Ramsey numbers... conjectured...

R = s,  (s-1),  (s-2) 2 k-s , (s-3) 2 k-s ,  etc. where s = unit group size
k = discussion group size

s = 4
k
R
s
(s-1)
(s-2) 2 k-s
(s-3) 2 k-s
4244321
51284442
6 640 4584
73,07246168
8 14,336 473216
965,536486432
10294,9124912864
11 1,310,720 410256128
125,767,168411512256
1325,165,8244121024512
14 109,051,904 4132,0481,024
15 469,762,048 4144,0962,048
162,013,265,9204158,1924,096
178,589,934,59241616,3848,192
1836,507,222,0164 1732,76816,384
19154,618,822,65641865,53632,768
20652,835,028,992419131,07265,536

s = 5
k
R
s
(s-1)
(s-2)
2 k-s
(s-3)
k-s
(s-4)
k-a
51205 4321
61,2005 5642
7 11,520 561284
8107,5205724168
9983,04058483216
10 8,847,360 59966432
1178,643,20051019212864
12692,060,160511384256128
136,039,797,760512768512256
1452,344,913,9205131,5361,024512
15450,971,566,0805143,0722,0481,024

s = 6
k
R
s
(s-1)
(s-2)
2k-s
(s-3)
k-s
(s-4)
k-s
(s-5)
k-s
672065 4321
7 13,824 6 6 8 6 4 2
8 258,0486 7161284
9 4,718,592 6 8 32 24 16 8
10 84,934,656 6 9 64 48 32 16
11 1,509,949,440 6 10 128 96 48 32
12 26,575,110,144 6 11 256 192 96 64
13 463,856,467,968 6 12 512 384 192 128

s = 7
k
R
s
(s-1)
(s-2)
2k-s
(s-3)
k-s
(s-4)
k-s
(s-5)
k-s
(s-6)
k-s
7 5,040 7 6 5 4 3 2 1
8 188,160 7 7 10 8 6 4 2
9 6,881,220 7 820161284
10 247,726,080 7 9403224168
11 8,808,038,400 7 108064483216
12 310,042,951,680 7 11160128966432

s = 8
k
R
s
(s-1)
(s-2)
2k-s
(s-3)
k-s
(s-4)
k-s
(s-5)
k-s
(s-6)
k-s
(s-7)
k-s
8 40,320 8 7 6 5 4 3 2 1
9 2,949,120 8 8 12 10 8 6 4 2
9 212,336,640 8 9 24 20 16 12 8 4
10 15,099,494,400 8 10 48 40 32 24 16 8

s = 9
k
R
s
(s-1)
(s-2)
2k-s
(s-3)
k-s
(s-4)
k-s
(s-5)
k-s
(s-6)
k-s
(s-7)
k-s
(s-8)
k-s
9 362,880 9 8 7 6 5 4 3 2 1
10 52,254,720 9 9 14 12 10 8 6 4 2
11 7,431,782,400 9 10 28 24 20 16 12 8 4

s = 10
k
R
s
(s-1)
(s-2)
2k-s
(s-3)
k-s
(s-4)
k-s
(s-5)
k-s
(s-6)
k-s
(s-7)
k-s
(s-8)
k-s
(s-9)
k-s
10 3,628,800 10 9 8 7 6 5 4 3 2 1
11 1,032,192,000 10 10 16 14 12 10 8 6 4 2
12 290,665,267,200 10 11 32 28 24 20 16 12 8 4


s = 11
k
R
s
(s-1)
(s-2)
2k-s
(s-3)
k-s
(s-4)
k-s
(s-5)
k-s
(s-6)
k-s
(s-7)
k-s
(s-8)
k-s
(s-9)
k-s
(s-10)
k-s
11 39,916,800 11 10 9 8 7 6 5 4 3 2 1
12 22,481,141,760 11 11 18 16 14 12 10 8 6 4 2


s = 12
k
R
s
(s-1)
(s-2)
2k-s
(s-3)
k-s
(s-4)
k-s
(s-5)
k-s
(s-6)
k-s
(s-7)
k-s
(s-8)
k-s
(s-9)
k-s
(s-10)
k-s
(s-11)
k-s
12 479,001,600 12 11 10 9 8 7 6 5 4 3 2 1
13 535,088,332,800 11 12 20 18 16 14 12 10 8 6 4 2

The remaining Ramsey numbers less than a trillion can also be seen as R! (factorial)

k
R
13 6,227,020,800
14 87,178,291,200

In total then, there are 34 basic Ramsey numbers
(unit group is 3) less than a trillion.
There are an additional 58 Ramsey numbers
(unit groups > 3) less than a trillion.

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